统计每个字母出现的次数，然后进行比较就行了。代码如下：

1 #include 
      
        2 #include 
       
         3 #include 
        
          4 using namespace std; 5  6 int main() 7 { 8 #ifdef LOCAL 9     freopen("in", "r", stdin);10 #endif11     char alpha[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";12     char s[110];13     while(scanf("%s", s) != EOF)14     {15         int len = strlen(s);16         int a[26];17         memset(a, 0, sizeof(a));18         for(int i = 0; i < len; i++)19             a[strchr(alpha, s[i])-alpha]++;20         scanf("%s", s);21         int b[26];22         memset(b, 0, sizeof(b));23         for(int i = 0; i < len; i++)24             b[strchr(alpha, s[i])-alpha]++;25         sort(a, a+26);26         sort(b, b+26);27         int i;28         for(i = 0; i < 26; i++)29             if(a[i] != b[i])   break;30         if(i == 26)   printf("YES\n");31         else printf("NO\n");32     }33     return 0;34 }35